3[(5x+1)-2]=2(4x-3)

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Solution for 3[(5x+1)-2]=2(4x-3) equation:


Simplifying
3[(5x + 1) + -2] = 2(4x + -3)

Reorder the terms:
3[(1 + 5x) + -2] = 2(4x + -3)

Remove parenthesis around (1 + 5x)
3[1 + 5x + -2] = 2(4x + -3)

Reorder the terms:
3[1 + -2 + 5x] = 2(4x + -3)

Combine like terms: 1 + -2 = -1
3[-1 + 5x] = 2(4x + -3)
[-1 * 3 + 5x * 3] = 2(4x + -3)
[-3 + 15x] = 2(4x + -3)

Reorder the terms:
-3 + 15x = 2(-3 + 4x)
-3 + 15x = (-3 * 2 + 4x * 2)
-3 + 15x = (-6 + 8x)

Solving
-3 + 15x = -6 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-3 + 15x + -8x = -6 + 8x + -8x

Combine like terms: 15x + -8x = 7x
-3 + 7x = -6 + 8x + -8x

Combine like terms: 8x + -8x = 0
-3 + 7x = -6 + 0
-3 + 7x = -6

Add '3' to each side of the equation.
-3 + 3 + 7x = -6 + 3

Combine like terms: -3 + 3 = 0
0 + 7x = -6 + 3
7x = -6 + 3

Combine like terms: -6 + 3 = -3
7x = -3

Divide each side by '7'.
x = -0.4285714286

Simplifying
x = -0.4285714286

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